(3c-5)(2c^2-c+8)=0

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Solution for (3c-5)(2c^2-c+8)=0 equation:


Simplifying
(3c + -5)(2c2 + -1c + 8) = 0

Reorder the terms:
(-5 + 3c)(2c2 + -1c + 8) = 0

Reorder the terms:
(-5 + 3c)(8 + -1c + 2c2) = 0

Multiply (-5 + 3c) * (8 + -1c + 2c2)
(-5(8 + -1c + 2c2) + 3c * (8 + -1c + 2c2)) = 0
((8 * -5 + -1c * -5 + 2c2 * -5) + 3c * (8 + -1c + 2c2)) = 0
((-40 + 5c + -10c2) + 3c * (8 + -1c + 2c2)) = 0
(-40 + 5c + -10c2 + (8 * 3c + -1c * 3c + 2c2 * 3c)) = 0
(-40 + 5c + -10c2 + (24c + -3c2 + 6c3)) = 0

Reorder the terms:
(-40 + 5c + 24c + -10c2 + -3c2 + 6c3) = 0

Combine like terms: 5c + 24c = 29c
(-40 + 29c + -10c2 + -3c2 + 6c3) = 0

Combine like terms: -10c2 + -3c2 = -13c2
(-40 + 29c + -13c2 + 6c3) = 0

Solving
-40 + 29c + -13c2 + 6c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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